Parameters for find function

beautifulsoup, find, python

Solution

Try using the alternative `attrs` keyword:

areaId = soupHandler.find('input', attrs={'name':'form_build_id', 'type':'hidden'})

You can't use a keyword argument called name because the Beautiful Soup search methods already define a name argument. You also can't use a Python reserved word like for as a keyword argument.

Beautiful Soup provides a special argument called attrs which you can use in these situations. attrs is a dictionary that acts just like the keyword arguments.

Problem

I'm using beautiful soup (in Python). I have such hidden input object: ``` <input type="hidden" name="form_build_id" id="form-531f740522f8c290ead9b88f3da026d2" value="form-531f740522f8c290ead9b88f3da026d2" /> ``` I need in id/value. Here is my code: ``` mainPageData = cookieOpener.open('http://page.com').read() soupHandler = BeautifulSoup(mainPageData) areaId = soupHandler.find('input', name='form_build_id', type='hidden') TypeError: find() got multiple values for keyword argument 'name' ``` I tried to change code: ``` print soupHandler.find(name='form_build_id', type='hidden') None ``` What's wrong?

Original source