TypeError: unsupported operand type(s) for |: 'tuple' and 'bool'

Question

I got strange error when I tried to use "|" operator in if with tuple. ``` #example Myset = ((1, 3), (4, 6), (3, 1), (2, 2), (3, 5), (2, 4), (3, 3)) courd = (4,6) if(courd[0] - 1 ,courd[1] - 1 in d ): isSafe = True # work as expected ``` but if I will try something like this: ``` if((courd[0] - 1 ,courd[1] - 1 in d) | 2==2 ): # or something else that involved "|" isSafe = True ``` I'm getting ``` Traceback (most recent call last): File "", line 1, in if((courd[0] - 1 ,courd[1] - 1 in d )| (2 == 2)): TypeError: unsupported operand type(s) for |: 'tuple' and 'bool' ```

Accepted Answer

You need to use parens, as needed, like this

```
if((courd[0] - 1, courd[1] - 1) in d):
    pass
```

Now, it will create a tuple `(courd[0] - 1, courd[1] - 1)` and it will check if it is in `d`. In the next case,

```
if((courd[0] - 1, courd[1] - 1 in d) | 2 == 2):
    pass
```

`(courd[0] - 1, courd[1] - 1 in d)` will be evaluated first and that will create a tuple. And then `2 == 2` will be evaluated (since `|` has lower precedence than `==`) to `True`, which is basically a boolean. So, you are effectively doing

```
tuple | boolean
```

That is why you are getting that error.

Note: `|` is called bitwise OR in Python. If you meant logical `OR`, you need to write it like this

```
if(((courd[0] - 1, courd[1] - 1) in d) or (2 == 2)):
    pass
```

Now, `(courd[0] - 1, courd[1] - 1)` will be evaluated first to create a tuple and then the tuple will be checked if it exists in `d` (this will return either `True` or `False`, a boolean) and then `(2 == 2)` will be evaluated which returns `True`. Now logical `or` would happily work with two booleans.

TypeError: unsupported operand type(s) for |: 'tuple' and 'bool'

Solution

Problem