C Program output confusion

Question

Can someone explain why the output of this program is false?? x && y gives 1. Still the output is false. ``` #include <stdio.h> int main() { int x = 1, y = 2; if(x && y == 1) { printf("true."); } else { printf("false."); } return 0; } ```

Accepted Answer

Because `==` has a higher precedence than `&&` So first this get's evaluated:

```
x && (y == 1)
```

```
y == 1  // 2 == 1
//Result: false
```

Which is false and then second:

```
x && false  //1 && false
//Result: false
```

So the if statement will be false

For more information about operator precedence see here: http://en.cppreference.com/w/cpp/language/operator_precedence

C Program output confusion

Solution

Problem