Git: Checkout only files without repository?
git
Solution
The git-archive manpage contains the following example:
`git archive --format=tar --prefix=junk/ HEAD | (cd /var/tmp/ && tar xf -)`
Create a tar archive that contains the contents of the latest commit on the current branch, and extract it in the '/var/tmp/junk' directory.
Or you can use low level git-checkout-index, which manpage contains the following example:
Using git checkout-index to "export an entire tree"
The prefix ability basically makes it trivial to use '`git checkout-index`' as an "export as tree" function. Just read the desired tree into the index, and do
$ git checkout-index --prefix=git-export-dir/ -a
`git checkout-index` will "export" the index into the specified directory.
The final "/" is important. The exported name is literally just prefixed with the specified string.
Or you can try to use `--work-tree` option to git wrapper, or GIT_WORK_TREE environment variable, e.g. by using "`git --work-tree=/somwehere/else checkout -- .`".
Problem
i'd like to just checkout the files without the .git files and the whole repository. It's because i'd like to manage a website (php & html) with git and i'm looking for an easy way to update the files in the htdocs folder from the repository, without having the repository public. (now it's in the home-dir and is accessed via ssh, but i have to put the new files to htdocs manually.