Regular Expression - Match pattern that does not contain a string
python, regex
Solution
Your syntax for trying to negate part of your pattern is incorrect.
Also, `^` outside of a character class asserts position at the beginning of the string. You need to use a Negative Lookahead assertion and be sure to anchor the entire pattern.
^abc(?:(?!abc).)*abc$
Live Demo
Problem
I'm quite new to regular expression, and have been searching around for away to do this without success. Given a string, I want to remove any pattern that starts with "abc", ends with "abc", and does not contain "abc" in the middle. If I do ``` 'abc.*(abc).*abc' ``` it will match any patter starts with "abc", ends with "abc", and does contain "abc" in the middle. How do I do the opposite. I try ``` 'abc.*^(abc).*abc' ``` but it won't work.