Writing a function pointer in c

c, function, function-pointers

Solution

int (*fn_pointer ( this_args ))( this_args );  

declares `fn_pointer` as a function that takes `this_args` and returns a pointer to a function that takes `this_args` as argument and returns an `int` type. It is equivalent to

typedef int (*func_ptr)(this_args);
func_ptr fn_pointer(this_args);

Let's understand it a bit more:

int f1(arg1, arg2);  // f1 is a function that takes two arguments of type   
                     // arg1 and arg2 and returns an int.

int *f2(arg1, arg2);  // f2 is a function that takes two arguments of type  
                      // arg1 and arg2 and returns a pointer to int.  

int (*fp)(arg1, arg2); // fp is a pointer to a function that takes two arguments of type  
                       // arg1 and arg2 and returns a pointer to int.  

int f3(arg3, int (*fp)(arg1, arg2)); // f3 is a function that takes two arguments of  
                                        // type arg3 and a pointer to a function that 
                                        // takes two arguments of type arg1 and arg2 and 
                                        // returns an int.  

int (*f4(arg3))(arg1, arg2); // f4 is a function that takes an arguments of type   
                             // arg3 and returns a pointer to a function that takes two 
                             // arguments of type arg1 and arg2 and returns an int   

How to read `int (*f4(arg3))(arg1, arg2);`

          f4                           -- f4
        f3(   )                        -- is a function
        f3(arg3)                       --  taking an arg3 argument
       *f3(arg3)                       --   returning a pointer
     (*f3(arg3))(    )                 --   to a function
    (*f3(arg3))(arg1, arg2)            --     taking arg1 and arg2 parameter
  int (*f3(arg3))(arg1, arg2)           --     and returning an int  

So, finally a home work :). Try to figure out the declaration

void (*signal(int sig, void (*func)(int)))(int);  

and use `typedef` to redefine it.

Problem

I was recently reading a code, and found that a function pointer is written as : ``` int (*fn_pointer ( this_args ))( this_args ) ``` I usually encounter a function pointer like this : ``` return_type (*fn_pointer ) (arguments); ``` Similar thing is discussed here: ``` // this is a function called functionFactory which receives parameter n // and returns a pointer to another function which receives two ints // and it returns another int int (*functionFactory(int n))(int, int) { printf("Got parameter %d", n); int (*functionPtr)(int,int) = &addInt; return functionPtr; } ``` Can somebody tell me what is the difference and how does this work ?

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