How do you format an unsigned long long int using printf?
c, format-specifiers, long-long, printf, syntax
Solution
Use the ll (el-el) long-long modifier with the u (unsigned) conversion. (Works in windows, GNU).
printf("%llu", 285212672);
Problem
``` #include <stdio.h> int main() { unsigned long long int num = 285212672; //FYI: fits in 29 bits int normalInt = 5; printf("My number is %d bytes wide and its value is %ul. A normal number is %d.\n", sizeof(num), num, normalInt); return 0; } ``` Output: ``` My number is 8 bytes wide and its value is 285212672l. A normal number is 0. ``` I assume this unexpected result is from printing the `unsigned long long int`. How do you `printf()` an `unsigned long long int`?