Java split is eating my characters
java, regex, split, string
Solution
Use zero-width matching assertions:
String str = "la$le\\$li$lo";
System.out.println(java.util.Arrays.toString(
str.split("(?<!\\\\)\\$")
)); // prints "[la, le\$li, lo]"
The regex is essentially
(?<!\\)\$
It uses negative lookbehind to assert that there is not a preceding `\`.
See also
- regular-expressions.info/Lookarounds
More examples of splitting on assertions
Simple sentence splitting, keeping punctuation marks:
String str = "Really?Wow!This.Is.Awesome!";
System.out.println(java.util.Arrays.toString(
str.split("(?<=[.!?])")
)); // prints "[Really?, Wow!, This., Is., Awesome!]"
Splitting a long string into fixed-length parts, using `\G`
String str = "012345678901234567890";
System.out.println(java.util.Arrays.toString(
str.split("(?<=\\G.{4})")
)); // prints "[0123, 4567, 8901, 2345, 6789, 0]"
Using a lookbehind/lookahead combo:
String str = "HelloThereHowAreYou";
System.out.println(java.util.Arrays.toString(
str.split("(?<=[a-z])(?=[A-Z])")
)); // prints "[Hello, There, How, Are, You]"
Related questions
- Can you use zero-width matching regex in String split?
- Backreferences in lookbehind
- How do I convert CamelCase into human-readable names in Java?
Problem
I have a string like this `String str = "la$le\\$li$lo"`. I want to split it to get the following output `"la","le\\$li","lo"`. The \$ is a $ escaped so it should be left in the output. But when I do `str.split("[^\\\\]\\$")` y get `"l","le\\$l","lo"`. From what I get my regex is matching a$ and i$ and removing then. Any idea of how to get my characters back? Thanks