How to get the parent dir location
path, python
Solution
You can apply dirname repeatedly to climb higher: `dirname(dirname(file))`. This can only go as far as the root package, however. If this is a problem, use `os.path.abspath`: `dirname(dirname(abspath(file)))`.
Problem
this code is get the templates/blog1/page.html in b.py: ``` path = os.path.join(os.path.dirname(__file__), os.path.join('templates', 'blog1/page.html')) ``` but i want to get the parent dir location: ``` aParent |--a | |---b.py | |---templates | |--------blog1 | |-------page.html |--templates |--------blog1 |-------page.html ``` and how to get the aParent location thanks updated: this is right: ``` dirname=os.path.dirname path = os.path.join(dirname(dirname(__file__)), os.path.join('templates', 'blog1/page.html')) ``` or ``` path = os.path.abspath(os.path.join(os.path.dirname(__file__),"..")) ```