Getting parts of a URL (Regex)
language-agnostic, regex, url
Solution
A single regex to parse and breakup a full URL including query parameters and anchors e.g.
https://www.google.com/dir/1/2/search.html?arg=0-a&arg1=1-b&arg3-c#hash
`^((http[s]?|ftp):\/)?\/?([^:\/\s]+)((\/\w+)*\/)([\w\-\.]+[^#?\s]+)(.*)?(#[\w\-]+)?$`
RexEx positions:
url: RegExp['$&'],
protocol:RegExp.$2,
host:RegExp.$3,
path:RegExp.$4,
file:RegExp.$6,
query:RegExp.$7,
hash:RegExp.$8
you could then further parse the host ('.' delimited) quite easily.
What I would do is use something like this:
/*
^(.*:)//([A-Za-z0-9\-\.]+)(:[0-9]+)?(.*)$
*/
proto $1
host $2
port $3
the-rest $4
the further parse 'the rest' to be as specific as possible. Doing it in one regex is, well, a bit crazy.
Problem
Given the URL (single line): http://test.example.com/dir/subdir/file.html How can I extract the following parts using regular expressions: - The Subdomain (test) - The Domain (example.com) - The path without the file (/dir/subdir/) - The file (file.html) - The path with the file (/dir/subdir/file.html) - The URL without the path (http://test.example.com) - (add any other that you think would be useful) The regex should work correctly even if I enter the following URL: ``` http://test.example.com/example/example/example.html ```