How to check which exception type was thrown in Java?
exception, java
Solution
If you can, always use separate `catch` blocks for individual exception types, there's no excuse to do otherwise:
} catch (NotAnInt e) {
// handling for NotAnInt
} catch (ParseError e) {
// handling for ParseError
}
...unless you need to share some steps in common and want to avoid additional methods for reasons of conciseness:
} catch (NotAnInt | ParseError e) {
// a step or two in common to both cases
if (e instanceof NotAnInt) {
// handling for NotAnInt
} else {
// handling for ParseError
}
// potentially another step or two in common to both cases
}
however the steps in common could also be extracted to methods to avoid that `if`-`else` block:
} catch (NotAnInt e) {
inCommon1(e);
// handling for NotAnInt
inCommon2(e);
} catch (ParseError e) {
inCommon1(e);
// handling for ParseError
inCommon2(e);
}
private void inCommon1(e) {
// several steps
// common to
// both cases
}
private void inCommon2(e) {
// several steps
// common to
// both cases
}
Problem
How can I determine which type of exception was caught, if an operation catches multiple exceptions? This example should make more sense: ``` try { int x = doSomething(); } catch (NotAnInt | ParseError e) { if (/* thrown error is NotAnInt */) { // line 5 // printSomething } else { // print something else } } ``` On line 5, how can I check which exception was caught? I tried `if (e.equals(NotAnInt.class)) {..}` but no luck. NOTE: `NotAnInt` and `ParseError` are classes in my project that extend `Exception`.