How to create generic closures in Swift

block, closures, swift

Solution

You cannot pass a closure of type `String->Void` to a parameter of type `AnyObject->Void`.

However, you can define a generic function:

func saveWithCompletionObject<T>(obj : T, success : T -> Void, failure : Void -> Void) {
    // ...
    success(obj)
}

Now the compiler can verify that `obj` has the same type as the parameter of `success`, for example:

func doSomething(success : String -> Void, failure : Void -> Void)
{
    saveWithCompletionObject("Example", success, failure)
}

func doSomethingElse(success : Int -> Void, failure : Void -> Void)
{
    saveWithCompletionObject(13, success, failure)
}

But I would recommend that `saveWithCompletionObject` just takes a `Void->Void` parameter (without generics):

func saveWithCompletionObject(success : Void -> Void, failure : Void -> Void) {
    // ...
    success()
}

and the caller wraps its closure:

func doSomething(success : String -> Void, failure : Void -> Void)
{
    saveWithCompletionObject( { success("Example") } , failure)
}

func doSomethingElse(success : Int -> Void, failure : Void -> Void)
{
    saveWithCompletionObject( { success(13) }, failure)
}

This is more flexible, e.g. for callback functions with more than one parameter:

func andNowForSomethingCompletelyDifferent(success : (Int, Double) -> Void, failure : Void -> Void)
{
    saveWithCompletionObject( { success(13, M_PI) }, failure)
}

Problem

I would like to create a function that uses generic closure (block) in swift. My first attempt was to do like : ``` func saveWithCompletionObject(obj : AnyObject, success : AnyObject -> Void, failure : Void -> Void) ``` But as soon as I call this function with another block, such as : ``` func doSomething(success : String -> Void, failure : Void -> Void) { saveWithCompletionObject("Example", success, failure) } ``` I get an error : `'AnyObject' is not a subtype of 'String'` Thanks in advance !

Original source