Shorten path to C++ enum member (using typedef or typename), to use as template parameter
c++, enums, shorthand, templates, typedef
Solution
Enumerators are values, not types. If you only need this particular enumerator, declare a constant:
const auto MyONE = MyNamespace::MyClass::MySubStruct::ONE;
If you need more than only this one, it could be feasible to add a typedef for `MySubStruct` and access the enumerators through that.
Problem
I have a rather complicated object, ``` MyNamespace::MyClass::MySubStruct ``` which has an ``` enum { ONE = 1, TWO = 2 }; ``` Now I have another class which has a template parameter ``` template <unsigned int x> class Foo; ``` Currently I initialize B as follows ``` Foo<MyNamespace::MyClass::MySubStruct::ONE> MyFoo ``` and that works just fine, but it is a bit too lengthy, especially given that I initialize this class about a hundred times. I would like to write something like: ``` typedef MyNamespace::MyClass::MySubStruct::ONE MyONE Foo<MyOne> MyFoo ``` Naturally, this does not compile, and neither does declaring it as a const unsigned int inside the class. How would one do this elegantly?