Equivalent to *args in Swift?
ios, swift, swift-playground, xcode
Solution
Something like this?
func concatOf(args: Any...) -> String {
var concat = ""
for arg in args {
concat = "\(concat)\(arg)"
}
return concat
}
Problem
``` func sumOf(numbers: Int...) -> Int { var sum: Int = 0 for number in numbers { sum += number } return sum } sumOf(1, 2, 3) //6 ``` This is sample code taken from the `Swift` iBook. It finds the sum of any number of arguments. A python equivalent of this code would be: ``` def sumOf(*args): sum = 0 for number in args: sum += number return sum sumOf(1, 2, 3) #6 ``` In python, *args accepts all variable types, so if I want to do this for whatever reason, I can: ``` def sumOf(*args): sum = "" for number in args: sum += str(number) return sum sumOf(1, "test", 3) #"1test3" ``` How do I do this in `Swift`? How do I create a function that has a variable number of parameters of ANY TYPE? I don't need to do this, but I'd like to know how. Thanks.