Does while loop have two Arguments?
c, c++, g++, while-loop
Solution
The comma operator is a binary operator and it evaluates its first operand and discards the result, it then evaluates the second operand and returns this value.
so in your case,
First it will increment i and j upto 5 and discard.
Second it will iterate i and i upto 10 and provide you the result as 10, 10.
you can confirm by using the following code,
while (i < 5, j < 10) // Doubt: how does while accept 2 arguments?? and how it works??
{
i++;
j+ = 2;
}
Problem
My ma'am gave me one question to solve. To predict the output of the following code. ``` #include <stdio.h> int main() { int i = 0, j = 0; printf("Output is : "); while (i < 5, j < 10) // Doubt: how does while accept 2 arguments?? and how it works?? { i++; j++; } printf("%d, %d\n", i, j); } ``` I thought it was a syntax error. But when I tried to run, it gave me output. ``` Output is : 10, 10 ``` But How? Can anyone explain? But if I remove the first printf statement `printf("Output is : ");` and run it, my antivirus give me a alert that a `Trojan` is detected. But how it becomes a `Trojan`?