BeautifulSoup: TypeError: 'NoneType' object is not subscriptable
beautifulsoup, html, html-parsing, python
Solution
My guess is that `label_tag` isn't actually returning the part of the soup you are looking for. This minimal example works:
import bs4
text = '''<a class="Label" href="_link_">_text_</a>'''
soup = bs4.BeautifulSoup(text)
link = soup.find("a",{"class":"Label"})
print (link["href"])
Output:
_link_
Problem
I need take "href" attribute from a link (a) tag. I run ``` label_tag = row.find(class_='Label') print(label_tag) ``` and I get (sorry, I can't show link and text for privacy reasons) ``` <a class="Label" href="_link_">_text_</a> ``` of type ``` <class 'bs4.element.Tag'> ``` but when I run (as shown at BeautifulSoup getting href ) ``` tag_link = label_tag['href'] print(tag_link) ``` I guess the following error (on first command) ``` TypeError: 'NoneType' object is not subscriptable ``` Any clue? Thanks in advance [SOLVED] EDIT: I was making a mistake (looping over elements with heterogeneous structure)