Calling base class constructor
c++, default-constructor, derived-class, inheritance
Solution
It's allowed, but it's pointless, as the compiler will make the call for you. I'm afraid I don't feel like doing a Standard trawl this morning, though.
Problem
In the program below, is the line ``` Derived(double y): Base(), y_(y) ``` correct/allowed? That is, does it follow ANSI rules? ``` #include <iostream> class Base { public: Base(): x_(0) { std::cout << "Base default constructor called" << std::endl; } Base(int x): x_(x) { std::cout << "Base constructor called with x = " << x << std::endl; } void display() const { std::cout << x_ << std::endl; } protected: int x_; }; class Derived: public Base { public: Derived(): Base(1), y_(1.2) { std::cout << "Derived default constructor called" << std::endl; } Derived(double y): Base(), y_(y) { std::cout << "Derived constructor called with y = " << y << std::endl; } void display() const { std::cout << Base::x_ << ", " << y_ << std::endl; } private: double y_; }; int main() { Base b1; b1.display(); Derived d1; d1.display(); std::cout << std::endl; Base b2(-9); b2.display(); Derived d2(-8.7); d2.display(); return 0; } ```