Kivy : how to get widget by id (without kv)
kivy, python, widget
Solution
Kivy widgets make tree structure. Children of any widget are avaiable through `children` atribute. If you want, you can keep reference only to root window and then iterate over it's widgets using `walk` method:
from kivy.app import App
from kivy.uix.boxlayout import BoxLayout
from kivy.uix.button import Button
class MyWidget(BoxLayout):
def __init__(self, **kwargs):
super().__init__(**kwargs)
button = Button(text="...", id="1")
button.bind(on_release=self.print_label)
l1 = BoxLayout(id="2")
l2 = BoxLayout(id="3")
self.add_widget(l1)
l1.add_widget(l2)
l2.add_widget(button)
def print_label(self, *args):
for widget in self.walk():
print("{} -> {}".format(widget, widget.id))
class MyApp(App):
def build(self):
return MyWidget()
if __name__ == '__main__':
MyApp().run()
`walk()` and `walk_reverse()` method were added to `kivy.uix.widget.Widget` in 1.8.1 version of Kivy. For older versions you need to recursively parse tree yourself:
from kivy.app import App
from kivy.uix.boxlayout import BoxLayout
from kivy.uix.button import Button
class MyWidget(BoxLayout):
def __init__(self, **kwargs):
super().__init__(**kwargs)
button = Button(text="...", id="1")
button.bind(on_release=self.print_label)
l1 = BoxLayout(id="2")
l2 = BoxLayout(id="3")
self.add_widget(l1)
l1.add_widget(l2)
l2.add_widget(button)
def print_label(self, *args):
children = self.children[:]
while children:
child = children.pop()
print("{} -> {}".format(child, child.id))
children.extend(child.children)
class MyApp(App):
def build(self):
return MyWidget()
if __name__ == '__main__':
MyApp().run()
Problem
Let's say I define on the fly in Kivy a few widgets (buttons) and dynamically assign their id. I'm not using kv language in this use case. I can keep a reference of a widget id without keeping track of the widget itself : then I'd like to access the widget through its id. Can I do something like "get widget by id" ? (If I had defined the widget in a kv file, I could have used self.ids.the_widget_id to access the widget itself through its id)