How to convert XmlNode into XElement?

.net, c#, linq, linq-to-xml

Solution

var xElem = XElement.Load( xmlElement.CreateNavigator().ReadSubtree() );

There are two problems with xmlElement.InnerXml used in other answer,

1- You will loose the root element (Of course, it can be handled easily)

XmlDocument doc = new XmlDocument();
doc.LoadXml("<root> <sub>aaa</sub> </root>");
var xElem1 = XElement.Load(doc.DocumentElement.CreateNavigator().ReadSubtree());
var xElem2 = XElement.Parse(doc.DocumentElement.InnerXml);

`xElem2` will be `<sub>aaa</sub>`, without(`root`)

2- You will get exception if your xml contains text nodes

XmlDocument doc = new XmlDocument();
doc.LoadXml("<root> text <sub>aaa</sub> </root>");
var xElem1 = XElement.Load(doc.DocumentElement.CreateNavigator().ReadSubtree());
var xElem2 = XElement.Parse(doc.DocumentElement.InnerXml); //<-- XmlException

Problem

I have an old `XmlNode`-based code. but the simplest way to solve my current task is to use `XElement` and LINQ-to-XML. The only problem is that there is no direct or obvious method for converting a `XmlNode` to a `XElement` in .NET Framework. So for starters, I want to implement a method that receives a `XmlNode` instance and converts it to a `XElement` instance. How can I implement this conversion?

Original source