append() to stuct that only has one slice field in golang

go

Solution

Two problems,

You're appending `*Element` to `[]Element`, either use `Element{}` or change the list to `[]*Element`.

You need to dereference the slice in `addElement`.

Example:

func (l *List) addElement(id string) {
    e := Element{
        Id: id,
    }
    *l = append(*l, e)
}

Problem

I want to append an element to a struct that only consists of a single annonymous slice: ``` package main type List []Element type Element struct { Id string } func (l *List) addElement(id string) { e := &Element{ Id: id, } l = append(l, e) } func main() { list := List{} list.addElement("test") } ``` That does not work, since addElement does not know l as slice but as *List: ``` go run plugin.go # command-line-arguments ./plugin.go:13: first argument to append must be slice; have *List ``` What most likely would work is to go like this: ``` type List struct { elements []Element } ``` and fix the addElement func accordingly. I there a nicer way than that, eg. one that let me keep the first definition of type List? Many thanks, sontags

Original source