Different pointer address printed inside function
c, pointers
Solution
The local variable `leaf` in the `main` is copied when `func` is invoked. This means, the local variable `leaf` inside `func` has the same value as `leaf` inside `main`, i.e. it points to the same memory address (thus equivalence for the second check), but it is itself stored at a different address.
Problem
I am new to C and pointers. The following is some code that i was experimenting with. ``` struct node{ struct node * next; struct node * prev; int num; }; void func(struct node * leaf , struct node ** add_leaf){ printf("function starts"); printf("&leaf = %p add_leaf = %p\n" , &leaf , add_leaf); printf("leaf = %p *add_leaf = %p\n" , leaf , *add_leaf); printf("function over"); return } void main(){ struct node * leaf = (struct node*)malloc(sizeof(struct node)); printf("leaf = %p\t&leaf = %p\n" , leaf , &leaf); func(leaf , &leaf); } ``` The values of leaf and *add_leaf are equal and that was what i expected. However I could not understand why was there a difference in the values of &leaf and add_leaf when printed inside the function. Here, I am trying to print the address of the node pointer leaf.