python, is function an object?
function, oop, python, python-2.7
Solution
The type of any function is `<type 'function'>`. The type of the type of function is `<type 'type'>`, like you got with `type(type(a))`. The reason `type(function)` doesn't work is because `type(function)` is trying to get the type of an undeclared variable called `function`, not the type of an actual function (i.e. `function` is not a keyword).
You are getting the metaclass error during your class definition because `a` is of type `function` and you can't subclass functions in Python.
Plenty of good info in the docs.
Problem
Given the following behaviour: ``` def a(): pass type(a) >> function ``` If type of `a` is `function`, what is `type` of `function`? ``` type(function) >> NameError: name 'function' is not defined ``` And why does `type` of `type` from `a` is `type`? ``` type(type(a)) >> type ``` Lastly: if `a` is an `object`, why it cannot be inherited? ``` isinstance(a, object) >> True class x(a): pass TypeError: Error when calling the metaclass bases function() argument 1 must be code, not str ```