Enumerable giving unexpected output
c#, enumerable, ienumerable
Solution
The second parameter of `Enumerable.Range` specifies the number of integers to generate, not the last integer in the range.
If necessary, it's easy enough to build your own method, or update your existing `Foo.Range` method, to generate a range from `start` and `end` parameters.
Problem
``` class Foo { public static IEnumerable<int> Range(int start, int end) { return Enumerable.Range(start, end); } public static void PrintRange(IEnumerable<int> r) { foreach (var item in r) { Console.Write(" {0} ", item); } Console.WriteLine(); } } class Program { static void TestFoo() { Foo.PrintRange(Foo.Range(10, 20)); } static void Main() { TestFoo(); } } ``` Expected Output: ``` 10 11 12 13 14 15 16 17 18 19 20 ``` Actual Output: ``` 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 ``` What is the problem with this code? Whats happening?