Which is the simple and fast UNIX command to print all lines from the last occurrence of a pattern?
awk, perl, sed, unix
Solution
This might work for you (GNU sed):
sed 'H;/pattern/h;$!d;x;//!d' file
Stashes the last pattern and following lines in the hold space and at end-of-file prints them out.
Or using the same method in awk:
awk '{x=x ORS $0};/pattern/{x=$0};END{if(x ~ //)print x}' file
However on my machine jaypals way with sed seems to be the quickest:
tac file | sed '/pattern/q' | tac
Problem
Which is the simple and fast UNIX command to print all lines from the last occurrence of a pattern to the end of the file ? ``` sed -n '/pattern/,$p' file ``` This sed command prints from the first occurrence onwards.