Problem in understanding connectSlotsByName() in pyqt?

Question

I couldn't understand the connectSlotsByName() method which is predominently used by pyuic4.. As far the class is single in a PyQt file it's ok since we can use self which will be associated with a single object throughout.. But when we try to use various classes from different files the problem and the need to use connectSlotsByName() arises.. Here's what i encountered which is weird.. I created a stacked widget.. I placed my first widget on it.. It has a button called "Next >". On clicking next it hides the current widget and adds another widget which has the "click me" button.. The problem here is the click event for "click me" button in second is not captured.. It's a minimal example that i can give for my original problem.. Please help me.. This is file No.1..(which has the parent stacked widget and it's first page). On clicking next it adds the second page which has "clickme" button in file2.. ``` from PyQt4 import QtCore, QtGui import file2 class Ui_StackedWidget(QtGui.QStacked…

Accepted Answer

At first, here is the minimal working example:

```
from sys import argv, exit
from PyQt4 import QtCore, QtGui

class widget2(QtGui.QWidget):

def __init__(self, args):
        self.app = MainApp(args)
        QtGui.QWidget.__init__(self)
        self.setObjectName('I')

self._layout = QtGui.QVBoxLayout(self)
        self.setLayout(self._layout)

self.pushButtoninWidget2 = QtGui.QPushButton(self)
        self.pushButtoninWidget2.setObjectName("pushButtoninWidget2")
        self.pushButtoninWidget2.setText('Click NOW!')
        self._layout.addWidget(self.pushButtoninWidget2)

QtCore.QMetaObject.connectSlotsByName(self)

@QtCore.pyqtSlot()
    def on_pushButtoninWidget2_clicked(self):
        print("Hai")

class MainApp(QtGui.QApplication):
    def __init__(self, args):
        QtGui.QApplication.__init__(self, args)

if __name__ == "__main__":
    main = widget2(argv)
    main.show()
    exit(main.app.exec_())
```

When you trying to connect slots by name, you must give proper names to the slots and then someone (moc, uic, or you by calling connectSlotsByName) must connect them. Proper name for such a slot is: "on_PyQtObjectName_PyQtSignalName".

Note, that, if I'd omitted @QtCore.pyqtSlot() in the example, slot would be executed once for every appropriate overload (twice in this case).

You DO need to call connectSlotsByNames directly, cause there is no moc, which do it for you when you use QT in C++, and you do not use uic and .ui file. If you want to connect slots implicitly (I'm always doing so, except slots, connected directly in .ui), you'd better use more pytonish syntaxe: button.clicked.connect(self._mySlot).

And take a look at https://riverbankcomputing.com/static/Docs/PyQt5/signals_slots.html#connecting-slots-by-name

Problem in understanding connectSlotsByName() in pyqt?

Solution

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