how to return json encoded form errors in symfony

Question

I want to create a webservice to which I submit a form, and in case of errors, returns a JSON encoded list that tells me which field is wrong. currently I only get a list of error messages but not an html id or a name of the fields with errors here's my current code ``` public function saveAction(Request $request) { $em = $this->getDoctrine()->getManager(); $form = $this->createForm(new TaskType(), new Task()); $form->handleRequest($request); $task = $form->getData(); if ($form->isValid()) { $em->persist($task); $em->flush(); $array = array( 'status' => 201, 'msg' => 'Task Created'); } else { $errors = $form->getErrors(true, true); $errorCollection = array(); foreach($errors as $error){ $errorCollection[] = $error->getMessage(); } $array = array( 'status' => 400, 'errorMsg' => 'Bad Request', 'errorReport' => $errorCollection); // data to return via JSON } $response = new Response( json_encode( $array ) ); $response->headers->set( 'Content-Type', 'application/json' ); return $response;…

Accepted Answer

I've finally found the solution to this problem here, it only needed a small fix to comply to latest symfony changes and it worked like a charm:

The fix consists in replacing line 33

```
if (count($child->getIterator()) > 0) {
```

with

```
if (count($child->getIterator()) > 0 && ($child instanceof \Symfony\Component\Form\Form)) {
```

because, with the introduction in symfony of Form\Button, a type mismatch will occur in serialize function which is expecting always an instance of Form\Form.

You can register it as a service:

```
services:
form_serializer:
    class:        Wooshii\SiteBundle\FormErrorsSerializer
```

and then use it as the author suggest:

```
$errors = $this->get('form_serializer')->serializeFormErrors($form, true, true);
```

how to return json encoded form errors in symfony

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