Swift Equatable Protocol
ios, swift, xcode6
Solution
Move this function
func == (lhs: Cookie, rhs: Cookie) -> Bool {
return lhs.column == rhs.column && lhs.row == rhs.row
}
Outside of the cookie class. It makes sense this way since it's overriding the == operator at the global scope when it is used on two Cookies.
Problem
I was folling this tutorial for Swift: https://www.raywenderlich.com/125311/make-game-like-candy-crush-spritekit-swift-part-1 and came across this code: ``` func == (lhs: Cookie, rhs: Cookie) -> Bool { return lhs.column == rhs.column && lhs.row == rhs.row } ``` I wrote exactly that, but Xcode is giving my these errors: ``` Consecutive declarations on a line must be separated by ';' Expected declaration operators are only allowed at global scope ``` I found this code from apple's documentation: https://developer.apple.com/documentation/swift/equatable Which is very similar to what I wrote. Whats wrong? This seems like a bug to me. I am using Xcode 6 Beta 2 EDIT: This is my whole Cookie class: ``` class Cookie: Printable, Hashable { var column: Int var row: Int let cookieType: CookieType let sprite: SKSpriteNode? init(column: Int, row: Int, cookieType: CookieType) { self.column = column self.row = row self.cookieType = cookieType } var description: String { return "type:\(cookieType) square:(\(column),\(row))" } var hashValue: Int { return row * 10 + column } func ==(lhs: Cookie, rhs: Cookie) -> Bool { return lhs.column == rhs.column && lhs.row == rhs.row } } ```