why you can't use a type from a different package if it has the same 'signature' ? golang
go
Solution
Because they are separate types.
What you're after is an interface that Go can use to guarantee that the types contain the same signatures. Interfaces contain methods that the compiler can check against the types being passed in.
Here is a working sample: http://play.golang.org/p/IsMHkiedml
Go won't magically infer the type based on how you call it. It will only do this when it can guarantee that the argument at the call site matches that of the input interface.
Problem
I'm wondering why the functions are not working with types of the same kind ? See the following pseudo functions. Playground: http://play.golang.org/p/ZG1jU8H2ZJ ``` package main type typex struct { email string id string } type typey struct { email string id string } func useType(t *typex) { // do something } func main() { x := &typex{ id: "somethng", } useType(x) // works y := &typey{ id: "something", } useType(y) // doesn't work ?? } ```