Passing variables through URL to a flask app
flask, python
Solution
The first route describes a url with a value as part of the url. The second url describes a route with no variables, but with a query parameter in the url.
If you are using the first route, the url should look like `http://127.0.0.1/changeip/1.2.2.2`.
If you are using the second url, the route should look like `/changeip`, the function should be `def change_ip():`, and the value should be read from `request.args['ip']`.
Usually the route should describe any arguments that should always be present, and form or query params should be used for user-submitted data.
Problem
Well i've this in my flask app : ``` @app.route("/changeip/<ip>") def change_ip(ip) : return ip ``` Now if i invoke it like : ``` http://127.0.0.1:5000/changeip?ip=1.2.2.2 ``` It spits out "URL not found"...what is that i'm doing wrong here?