Android / Java: Check if url is valid youtube url

android, java, regex, youtube

Solution

This works for me.

public static boolean isYoutubeUrl(String youTubeURl)
{
       boolean success;
       String pattern = "^(http(s)?:\\/\\/)?((w){3}.)?youtu(be|.be)?(\\.com)?\\/.+";
       if (!youTubeURl.isEmpty() && youTubeURl.matches(pattern))
       {
           success = true;
       }
       else
       {
           // Not Valid youtube URL
           success = false;
       }
       return success;
  }

If you want to retrieve the Youtube videoId you can use the following function.

public static String getVideoIdFromYoutubeUrl(String youtubeUrl)
{
       /*
           Possibile Youtube urls.
           http://www.youtube.com/watch?v=WK0YhfKqdaI
           http://www.youtube.com/embed/WK0YhfKqdaI
           http://www.youtube.com/v/WK0YhfKqdaI
           http://www.youtube-nocookie.com/v/WK0YhfKqdaI?version=3&hl=en_US&rel=0
           http://www.youtube.com/watch?v=WK0YhfKqdaI
           http://www.youtube.com/watch?feature=player_embedded&v=WK0YhfKqdaI
           http://www.youtube.com/e/WK0YhfKqdaI
           http://youtu.be/WK0YhfKqdaI
        */
       String pattern = "(?<=watch\\?v=|/videos/|embed\\/|youtu.be\\/|\\/v\\/|\\/e\\/|watch\\?v%3D|watch\\?feature=player_embedded&v=|%2Fvideos%2F|embed%\u200C\u200B2F|youtu.be%2F|%2Fv%2F)[^#\\&\\?\\n]*";
       Pattern compiledPattern = Pattern.compile(pattern);
       //url is youtube url for which you want to extract the id.
       Matcher matcher = compiledPattern.matcher(youtubeUrl);
       if (matcher.find()) {
           return matcher.group();
       }
       return null;
}

Problem

I want to check if an url is valid youtube url so that I can shown in view otherwise I will hide the view. Is there any regular expression in Java that can help me to check if url is valid. Currently I am using this regex but I guess it's not the one I want: ``` String youTubeURl = "https://www.youtube.com/watch?v=Btr8uOU0BkI"; String pattern = "https?:\\/\\/(?:[0-9A-Z-]+\\.)?(?:youtu\\.be\\/|youtube\\.com\\S*[^\\w\\-\\s])([\\w\\-]{11})(?=[^\\w\\-]|$)(?![?=&+%\\w]*(?:['\"][^<>]*>|<\\/a>))[?=&+%\\w]*"; if (!youTubeURl.isEmpty() && youTubeURl.matches(pattern)) { /// Valid youtube URL } else{ // Not Valid youtube URL } ```

Original source