regex find characters between " "

Question

How can I match all characters between 2 specified characters, say `" "` -> from `sdfsf " 12asdf " sdf` I want to get `12asdf` only.

Accepted Answer

You can use the following pattern to get everything between `" "`, including the leading and trailing white spaces:

```
"(.*?)"
```

or

```
"([^"]*)"
```

If you want to capture everything between the " " excluding the leading and trailing white spaces you can do:

```
"\s*(.*?)\s*"
```

or

```
"\s*([^"]*)\s*"
```

Solution