Why isn't this a syntax error in python?
conditional-expressions, grammar, python
Solution
Whitespace between tokens
Except at the beginning of a logical line or in string literals, the whitespace characters space, tab and formfeed can be used interchangeably to separate tokens. Whitespace is needed between two tokens only if their concatenation could otherwise be interpreted as a different token (e.g., ab is one token, but a b is two tokens).
So in this case, `1if` is not a valid token, so the whitespace is optional. The `1` is interpreted as an integer literal of which the `if` is not a part. So `if` is interpreted separately and recognized as a keyword.
In `xif` however, an identifier is recognized, so Python is not able to see that you wanted to do `x if` there.
Problem
Noticed a line in our codebase today which I thought surely would have failed the build with syntax error, but tests were passing so apparently it was actually valid python (in both 2.x and 3). Whitespace is sometimes not required in the conditional expression: ``` >>> 1if True else 0 1 ``` It doesn't work if the LHS is a variable: ``` >>> x = 1 >>> xif True else 0 File "<stdin>", line 1 xif True else 0 ^ SyntaxError: invalid syntax ``` But it does seem to still work with other types of literals: ``` >>> {'hello'}if False else 'potato' 'potato' ``` What's going on here, is it intentionally part of the grammar for some reason? Is this odd quirk a known/documented behaviour?