How to separate float into an integer and a fractional part?
c, floating-point
Solution
There is a function included in `math.h` library called modf With this function you can do just what are you trying to.
Example:
#include <stdio.h>
#include <math.h>
double ftof ()
{
double floating = 3.40, fractional, integer;
fractional = modf(floating, &integer);
printf ("Floating: %g\nInteger: %g\nFractional: %g", floating, integer, fractional); // when using printf, there are no floats
return fractional;
}
Output:
Floating: 3.40
Integer: 3
Fractional: 0.40
Note that using `double` in most of the cases is better than using `float`, despite that `double` consumes twice the memory of `float` (4:8 bytes) hence the increased range and accuracy. Also in case you need more precise output from bigger floating numbers when printing, you can try the `printf()` exponent format specifier `%e` instead of `%g` which only uses the shortest representation of the floating decimal.
Problem
I am willing to cast precise operations and for that purpose I need a way to seperate a float number into an integer and a fractional part. Is there any way for this?