Checking for underflow/overflow in C++?
c++, integer-overflow, overflow, underflow
Solution
To check for over/underflow in arithmetic check the result compared to the original values.
uint32 a,b;
//assign values
uint32 result = a + b;
if (result < a) {
//Overflow
}
For your specific the check would be:
if (a > (c-b)) {
//Underflow
}
Problem
Is there a general way to check for an overflow or an underflow of a given data type (uint32, int etc.)? I am doing something like this: ``` uint32 a,b,c; ... //initialize a,b,c if(b < c) { a -= (c - b) } ``` When I print a after some iterations, it displays a large number like: 4294963846.