accessing wsdl on Tomcat

glassfish, java, jax-ws, tomcat, wsdl

Solution

The way to access a WSDL is not really container specific, it's more WS-stack specific. The WS-stack in GlassFish is Metro (Metro = JAX-WS RI + WSIT). Did you install/deploy Metro or JAX-WS RI on Tomcat? See Metro on Tomcat 6.x or Running JAX-WS Samples with Tomcat 6.x (JAX-WS RI might be enough in your case) for the steps.

Update: You need to declare the `WSServlet` in the `web.xml` (see Deploying Metro endpoint):

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
  <listener>
    <listener-class>
    com.sun.xml.ws.transport.http.servlet.WSServletContextListener
    </listener-class>
  </listener>
  <servlet>
    <servlet-name>WebServicePort</servlet-name>
    <servlet-class>
    com.sun.xml.ws.transport.http.servlet.WSServlet
    </servlet-class>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>WebServicePort</servlet-name>
    <url-pattern>/services/*</url-pattern>
  </servlet-mapping>
  <session-config>
    <session-timeout>60</session-timeout>
  </session-config>
</web-app>

And then in the `sun-jaxws.xml` (also packaged in WEB-INF), declare your Service Endpoint Interface (SEI):

<?xml version="1.0" encoding="UTF-8"?>
<endpoints xmlns="http://java.sun.com/xml/ns/jax-ws/ri/runtime" version="2.0">
  <endpoint
  name="MyHello"
  implementation="hello.HelloImpl"
  url-pattern="/hello"
  />
</endpoints>

And you access the WSDL at:

http://localhost:8080/<mycontext>/services/hello?wsdl
           A               B         C       D

- A is the host and port of the servlet container.

- B is the name of the war file.

- C comes from the url-pattern element in the web.xml file.

- D comes from the ending stem of the url-pattern attribute in the sun-jaxws.xml file.

Problem

I have a web service and I was deploying it on GlassFish. I accessed its wsdl through http://localhost:10697/APIService/APIServiceService?wsdl. Now I ported the WAR file to a Tomcat 6.0.24 and it is deployed. However I am trying to access its wsdl using http://localhost:8080/APIService/APIServiceService?wsdl but I'm getting a 404 error. I tried various combinations but none seem to work. How can I access the wsdl file plz? Thanks and regards, Update: Here you are: `web.xml`: ``` <?xml version="1.0" encoding="UTF-8"?> <web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <session-config> <session-timeout> 30 </session-timeout> </session-config> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> </web-app> ``` I can't find `sun-jaxws.xml` however... Thanks a lot! Regards

Original source