Weird boolean conversion (?)
c++
Solution
`(4==4==4)` is basically `((4==4)==4)` which is `(true == 4)` which is `(1==4)` 1 which is `false` 2 which is getting printed as `0`.
Note that `==` has associativity left-to-right, but that doesn't matter (in this case) because even if it had associativity right-to-left, the result would have been the same.
1. Due to integral promotion. 2. Note that one might tempted to think `4` in `(true==4)` could be treated as `true` (after all `4` is non-zero, hence `true`). This thinking might conclude `(true==4)` is `(true==true)` which is `true`. But that is not how it works. It is the bool which gets promoted to int, instead of int to bool.
Problem
Explain pleasy why second expression returns false ``` cout << (4==4) << endl; //1 cout << (4==4==4) << endl; // 0 ```