Java regex match each group separately

Question

I have a string like this: ``` String text = "new SingleSizeProduct(422056, 1265858, 5430, '3XL', 75, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265859, 5341, 'L', 55, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265860, 5459, 'M', 45, 1, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265861, 5446, 'S', 35, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265862, 5458, 'XL', 60, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265863, 5511, 'XXL', 65, 0, '14.90', '16.50', '29.90', 'TL')"; ``` and regex: ``` String regex = "new SingleSizeProduct((.*))"; ``` I want to match all 6 groups separately, but when I match the pattern, I get result like this: ``` ( [0] => new SingleSizeProduct(422056, 1265858, 5430, '3XL', 75, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265859, 5341, 'L', 55, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265860, 5459, 'M…

Accepted Answer

`.*` is greedy so it will try to find maximal possible match meaning that `(.*)` will match

```
abc(foo)def(bar)ghi
    ^^^^^^^^^^^
```

If you want to make it find minimal possible match

```
abc(foo)def(bar)ghi
    ^^^     ^^^
```

make `*` reluctant by adding `?` after it

```
String regex = "new SingleSizeProduct((.*?))";
```

Also you need to escape `(` and `)` because as you know they represent start-end of capturing groups.

```
String regex = "new SingleSizeProduct$(.*?)$";
```

BTW. Another solution would be using instead of `.*?` `[^)]*` which means, everything except `)`

```
String regex = "new SingleSizeProduct(([^)]*))";
```

Java regex match each group separately

Solution

Problem