Remove key from object/value using Lodash

Question

I am trying to end up with 2 arrays of objects, a & b. If the key 'name' appears in array a, I do not want it to appear in b. ``` var characters = [ { 'name': 'barney', 'blocked': 'a', 'employer': 'slate' }, { 'name': 'fred', 'blocked': 'a', 'employer': 'slate' }, { 'name': 'pebbles', 'blocked': 'a', 'employer': 'na' }, { 'name': 'pebbles', 'blocked': 'b', 'employer': 'hanna' }, { 'name': 'wilma', 'blocked': 'c', 'employer': 'barbera' }, { 'name': 'bam bam', 'blocked': 'c', 'employer': 'barbera' } ]; var a = _.filter(characters, { 'blocked': 'a' }); var z = _.pluck(a,'name'); var b = _.difference(characters, a); _(z).forEach(function (n) { //_.pull(b, _.filter(b, { 'name': n })); //b = _.without(b, { 'name': n }); // b = _.without(b, _.filter(b, { 'name': n })); _.without(b, _.filter(b, { 'name': n })); }); ``` The code runs, but array "b" is never altered. What I expect is for array "b" to have the two objects with the names wilma and bam bam. I tried doing it without a loop. ``` var…

Accepted Answer

You can use `remove()` inside the `forEach()` to achieve the result you want...

```
_(z).forEach(function (n) {
    _.remove(b, { 'name': n });
});
```

The code can be further simplified by removing `z` and `forEach()`...

```
var a = _.filter(characters, { 'blocked': 'a' });
var b = _(characters)
            .difference(a)
            .reject(function (x) { 
                return _.where(a, { 'name': x.name }).length; 
            })
            .value();
```

JSFiddle

Remove key from object/value using Lodash

Solution

Problem