Bash, argument list segment
arrays, bash
Solution
you can do "slicing" as well, `$@` gets all the arguments in bash.
echo "${@:2}"
gets 2nd argument onwards
eg
$ cat shell.sh
#!/bin/bash
echo "${@:2}"
$ ./shell.sh 1 2 3 4
2 3 4
Problem
If you have a list in python, and you want the elements from 2 to n can do something nice like ``` list[2:] ``` I'd like to something similar with argv in Bash. I want to pass all the elements from $2 to argc to a command. I currently have ``` command $2 $3 $4 $5 $6 $7 $8 $9 ``` but this is less than elegant. Would would be the "proper" way?