Python/Matplotlib Inverse Fill of Polar Plot Polygon

Question

Currently I have the following script that generates a polar plot of azimuth/radius data. "R1" is simple a list of values of [azimuth, inclination] derived from a table in ArcGIS. ``` import matplotlib.pyplot as plt import numpy as np for(a,r) in R1: angles.append(a) radius.append(90-r) theta = np.radians(angles) r = radius ax = plt.subplot(111,polar=True) ax.plot(theta, r, color='black', ls='-', linewidth=1) ax.fill(theta,r,'0.75') ## should I use ax.fill_betweenx() ? ax.set_theta_zero_location('N') ax.set_theta_direction(-1) ax.set_rmax(90) ax.set_rmin(0) ax.set_yticks(range(0,90,10)) yLabel=['90','','','60','','','30','','',''] ax.set_yticklabels(yLabel) ax.grid(True) plt.show() ``` At the moment this creates the following plot: How can I "invert" the fill so that what is filled with gray will be white, and what is white will be gray? I have tried ax.fill_betweenx(theta,90,r,color='0.75') and that didn't work. I have been battling with this for some time now to no avail. ANY help o…

Accepted Answer

Depending on what you want to do with this later, the quickest way is to simply make the background gray and the fill white:

```
import matplotlib.pyplot as plt
import numpy as np
ax = plt.subplot(111, polar=True)

theta = np.linspace(0, 2*np.pi, 100)
r = 2 + np.sin(theta * 2)
ax.patch.set_facecolor('0.5')
ax.plot(theta, r, color='black', ls='-', linewidth=1)
ax.fill(theta,r,'w')
plt.show()
plt.draw() # just to be safe!
```

Python/Matplotlib Inverse Fill of Polar Plot Polygon

Solution

Problem