how to use paginator::make() in laravel to show resultset in view?

Question

I have used `Paginator::make` to paginate the records in the table. In the view, I am getting the pagination links, but every link has all the records in it. How to restrict it to `perPage` items? ``` $datas = Paginator::make($paginator, count($paginator), $perPage); return $datas; ``` The code outputs: ``` {"total":10,"per_page":5,"current_page":1,"last_page":2,"from":1,"to":5,"data": [{"id":"10","languages":"ds","created_at":"2014-05-23 11:59:02.000","created_by":"1","updated_at":"2014-05-23 11:59:02.000","updated_by":"1","is_active":"1"}, {"id":"9","languages":"urdu","created_at":"2014-05-23 11:57:24.000","created_by":"1","updated_at":"2014-05-23 11:57:24.000","updated_by":"1","is_active":"1"}, {"id":"8","languages":"were","created_at":"2014-05-23 11:55:49.000","created_by":"1","updated_at":"2014-05-23 11:55:49.000","updated_by":"1","is_active":"1"}, {"id":"7","languages":"delete","created_at":"2014-05-23 11:54:57.000","created_by":"1","updated_at":"2014-05-24 06:02:46.000","update…

Accepted Answer

Actually Paginator::make function we need to pass only the required values instead of all values. Because paginator::make function simply displays the data send to it. To send the correct offset paginated data to the paginator::make, the following method should be followed

```
    $paginator = json_decode($response);
    $perPage = 5;   
    $page = Input::get('page', 1);
    if ($page > count($paginator) or $page < 1) { $page = 1; }
    $offset = ($page * $perPage) - $perPage;
    $articles = array_slice($paginator,$offset,$perPage);
    $datas = Paginator::make($articles, count($paginator), $perPage);
```

Hope this will help someone...

how to use paginator::make() in laravel to show resultset in view?

Solution

Problem