How can I get a uitableViewCell by indexPath?

Question

How can I get a `UITableViewCell` by `indexPath`? Like this: I use the `UIActionSheet`, when I click confirm `UIButton` I want to change the cell text. The nowIndex I define as a property ``` - (void)actionSheet:(UIActionSheet *)actionSheet clickedButtonAtIndex:(NSInteger)buttonIndex { if (buttonIndex == 0) { NSInteger section = [nowIndex section]; NSInteger row = [nowIndex row]; NSDateFormatter *formatter = [[[NSDateFormatter alloc] init] autorelease]; formatter.dateFormat = @"yyyy-MM-dd"; if (section == 0) { if (row == 0) { } else if (row == 1) { UILabel *content = (UILabel *)[[(UITableView *)[actionSheet ] cellForRowAtIndexPath:nowIndex] viewWithTag:contentTag]; content.text = [formatter stringFromDate:checkInDate.date]; } else if (row == 2) { } } } } ```

Accepted Answer

```
[(UITableViewCell *)[(UITableView *)self cellForRowAtIndexPath:nowIndex]
```

will give you uitableviewcell. But I am not sure what exactly you are asking for! Because you have this code and still you asking how to get uitableviewcell. Some more information will help to answer you :)

ADD: Here is an alternate syntax that achieves the same thing without the cast.

```
UITableViewCell *cell = [self.tableView cellForRowAtIndexPath:nowIndex];
```

How can I get a uitableViewCell by indexPath?

Solution

Problem