JavaScript: Compare the structure of two JSON objects while ignoring their values

comparison, javascript, json

Solution

This is an elegant solution. You could do it simple like this:

var equal = true;
for (i in object1) {
    if (!object2.hasOwnProperty(i)) {
        equal = false;
        break;
    }
}

If the two elements have the same properties, then, the var `equal` must remain `true`.

And as function:

function compareObjects(object1, object2){
    for (i in object1)
        if (!object2.hasOwnProperty(i))
            return false;
    return true;
}

Problem

I use a Node.js based mock server for specifying and mocking API responses from a backend. It would greatly help to have some kind of check if both backend and frontend comply with the specification. In order to do that, I need some kind of method of comparing the structure of two JSON Objects. For example those two objects should be considered equal: ``` var object1 = { 'name': 'foo', 'id': 123, 'items' : ['bar', 'baz'] } var object2 = { 'name': 'bar', 'items' : [], 'id': 234 } ``` Any ideas how I would go about that?

Original source

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