Multiple assignment of non-tuples in scala

Question

Just to clarify, when I say multiple assigment, parallel assignment, destructuring bind I mean the following pattern matching gem ``` scala> val (x,y) = Tuple2("one",1) x: java.lang.String = one y: Int = 1 ``` which assigns `"one"` to `x` and `1` to `y`. I was trying to do ``` val (x,y) = "a b".split() ``` I was expecting that scala would attempt to pattern match the array with the pattern, and would throw a runtime exception if the length of the array wouldn't match the length of the pattern. All my attempts to easily convert an `Array` to a `Tuple2` were futile. ``` scala> Tuple2(Array(1,2):_*) :7: error: wrong number of arguments for method apply: (T1,T2)(T1, T2) in object Tuple2 Tuple2(Array(1,2):_*) ^ scala> Tuple2(Array(1,2).toList:_*) :7: error: wrong number of arguments for method apply: (T1,T2)(T1, T2) in object Tuple2 Tuple2(Array(1,2).toList:_*) ``` Is there any neat way to use multiple assignment with arrays or lists?

Accepted Answer

All you need to do is make your val side (left of the `=`) compatible with your initializer (right of the `=`):

```
scala> val Array(x, y, z) = "XXX,YYY,ZZZ".split(",")
x: java.lang.String = XXX
y: java.lang.String = YYY
z: java.lang.String = ZZZ
```

As you expected, a `scala.MatchError` will be thrown at runtime if the array size don't match (isn't 3, in the above example).

Multiple assignment of non-tuples in scala

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