PHP seems to be evaluating an if statement backwards

operator-precedence, php

Solution

You have operator precedence issue. Check this http://www.php.net/manual/en/language.operators.precedence.php

Because `||` has higher precedence than `=` Your expression really looks like this

if ( 
    $x = ( 
        function($y) || ( $z == 50 ) 
    ) 
)

Instead of (what I think was your intention)

if ( 
    ($x = function($y)) || ($z == 50) 
)

Problem

So I have a PHP statement of the following type: `if ($x=function($y) || $z == 50) {` What I see happening is that if $z is 50, $x doesn't get set because the function is never called. Is that really possible? I can (and did) fix this easily, but I guess I am confused that that's what is happening and want to make sure I don't make mistakes like this going forward I tried to find out how OR expressions like this are evaluated. Is there a place I can look to see how php gets "compiled"?

Original source

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