How Type.GetType works when given partially qualified type name?
.net, types
Solution
If the DLL it's in isn't already loaded into the application domain (e.g. you used it), you need the full path like this, if it's already loaded, it can find it with the shorter version.
To answer your question: the second version always works, stick with it and you have one way to worry about.
Problem
In numerous places do I encounter partially qualified type names of the form `FullTypeName, AssemblyName`, i.e. like `Type.AssemblyQualifiedName` only without the version, culture and publicKeyToken qualifiers. My question is how can one convert it to the respective `Type` in a minimum of effort? I thought that `Type.GetType` does the job, but alas, it does not. The following code, for instance, returns `null`: ``` Type.GetType("System.Net.Sockets.SocketException, System"); ``` Of course, if I specify the fully qualified name it does work: ``` Type.GetType("System.Net.Sockets.SocketException, System, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089"); ``` Thanks a lot.