How to get nested dictionary key value with .get()
dictionary, nested, nested-properties, python
Solution
`dict.get` accepts additional `default` parameter. The `value` is returned instead of `None` if there's no such key.
print myDict.get('key1', {}).get('attr3')
Problem
With a simple dictionary like: ``` myDict = {'key1':1, 'key2':2} ``` I can safely use: ``` print myDict.get('key3') ``` and even while 'key3' is not existent no errors will be thrown since .get() still returns None. Now how would I achieve the same simplicity with a nested keys dictionary: ``` myDict={} myDict['key1'] = {'attr1':1,'attr2':2} ``` The following will give a KeyError: ``` print myDict.get('key1')['attr3'] ``` This will go through: ``` print myDict.get('key1').get('attr3') ``` but it will fail with adn AttributeError: 'NoneType' object has no attribute 'get': ``` print myDict.get('key3').get('attr1') ```