PHP If undefined set default value on GET value

Question

I have the below form where I am putting in a value in my field which is different depending if there is anything to GET or not. What I have works but I am wondering if there is more efficient way of coding this, as my real form will have around 10 input fields and I don't want to be adding 6 lines of code each time I add a new input field? ``` ``` I have tried to also do ``` ``` This puts in a value of 0 into my form but I get the error Notice: Undefined index: name

Accepted Answer

Use `isset()` in the ternary operator:

```
$name = isset($_GET["name"]) ? $_GET["name"] : 0;
```

You get the notice because you evaluate `$_GET['name']` directly, without using `isset()` or `empty()` wrapper.

You might prefer to make a resuble function to simply your code:

```
function filterThing($key){
    return isset($_GET[$key]) ? $_GET[$key] : 0;
}

$name = filterThing('name');
$type = filterThing('type');
$other = filterThing('other');
```

PHP If undefined set default value on GET value

Solution

Problem