How to sort all dataframes in a list of dataframes on the same column?
dataframe, r, sorting
Solution
Use `lapply`:
sorted_dataframes_list <- lapply(dataframes_list, function(df){
df[order(df$enrichment),]
})
Problem
I have a list of dataframes `dataframes_list`. For an example, I put the `dput(dataframes_list)` at the bottom. I want to sort all dataframes in the list on the column `enrichment`. I can sort one dataframe with ``` first_dataframe <- dataframes_list[[1]] sorted_dataframe <- first_dataframe[order(first_dataframe$enrichment),] ``` How can I do this for every dataframe in `dataframes_list`? example `dataframes_list`: ``` list(structure(list(rank = c(1, 2, 3, 4, 5, 6), cmap.name = c("meclocycline", "pimozide", "isocorydine", "alvespimycin", "15-delta prostaglandin J2", "naloxone"), mean = c(-0.471, 0.504, -0.49, 0.193, 0.296, -0.383 ), n = c(4, 4, 4, 12, 15, 6), enrichment = c(-0.869, 0.855, -0.859, 0.539, 0.476, -0.694), p = c("0.00058", "0.00058", "0.00068", "0.00072", "0.00122", "0.00199"), specificity = c("0", "0.0302", "0", "0.069", "0.2961", "0.0155"), percent.non.null = c(100, 100, 100, 50, 60, 83), signature_name = c("day1_day3__sham3_strict", "day1_day3__sham3_strict", "day1_day3__sham3_strict", "day1_day3__sham3_strict", "day1_day3__sham3_strict", "day1_day3__sham3_strict")), .Names = c("rank", "cmap.name", "mean", "n", "enrichment", "p", "specificity", "percent.non.null", "signature_name"), row.names = c(NA, 6L), class = "data.frame"), structure(list(rank = c(1, 2, 3, 4, 5, 6), cmap.name = c("trichostatin A", "daunorubicin", "ketotifen", "quipazine", "minoxidil", "ricinine" ), mean = c(-0.319, -0.515, 0.486, 0.476, 0.316, -0.481), n = c(182, 4, 4, 4, 5, 4), enrichment = c(-0.384, -0.883, 0.862, 0.861, 0.812, -0.816), p = c("0", "0.00046", "0.0005", "0.0005", "0.00058", "0.00209"), specificity = c("0.3762", "0.0175", "0.0053", "0.0065", "0", "0.006"), percent.non.null = c(56, 100, 100, 100, 60, 100), signature_name = c("hour4_day1_day3__sham3_strict", "hour4_day1_day3__sham3_strict", "hour4_day1_day3__sham3_strict", "hour4_day1_day3__sham3_strict", "hour4_day1_day3__sham3_strict", "hour4_day1_day3__sham3_strict")), .Names = c("rank", "cmap.name", "mean", "n", "enrichment", "p", "specificity", "percent.non.null", "signature_name"), row.names = c(NA, 6L), class = "data.frame")) ```