Regex for ONE-or-more letters/digits And ZERO-or-more spaces
java, regex
Solution
I believe you can do something like this:
([ ]*+[0-9A-Za-z]++[ ]*+)+
This is 0 or more spaces, followed by at least 1 alphanum char, followed by 0 or more spaces
^^ that whole thing at least once.
Using Pshemo's idea of possessive quantifiers to speed up the regex.
Problem
I want to allow 0 or more white spaces in my string and one or more A-Z or a-z or 0-9 in my string. Regex allowing a space character in Java suggests `[0-9A-Za-z ]+`. I doubt that, this regex matches patterns having zero or more white spaces. What to do to allow 0 or more whitespaces anywhere in the string and one or more characters anywhere in the string. Will this work? `([0-9A-Za-z]+)([ ]*)`